可以使用Array.filter()和Array.find()方法来实现数组之间的比较和筛选。具体步骤如下：

1. 定义两个对象数组：

const arr1 = [
  {id: 1, name: 'John'},
  {id: 2, name: 'Mark'},
  {id: 3, name: 'Mary'}
];

const arr2 = [
  {id: 1, salary: 50000},
  {id: 2, salary: 60000},
  {id: 4, salary: 70000}
];

2. 使用Array.filter()方法来找到两个数组中共有的对象，即拥有相同id属性的对象：

const common = arr1.filter(obj1 => arr2.find(obj2 => obj2.id === obj1.id));

3. 使用Array.filter()方法来找到在arr1中存在而在arr2中不存在的对象：

const onlyInArr1 = arr1.filter(obj1 => !arr2.find(obj2 => obj2.id === obj1.id));

4. 使用Array.filter()方法来找到在arr2中存在而在arr1中不存在的对象：

const onlyInArr2 = arr2.filter(obj2 => !arr1.find(obj1 => obj1.id === obj2.id));

完整代码示例：

const arr1 = [
  {id: 1, name: 'John'},
  {id: 2, name: 'Mark'},
  {id: 3, name: 'Mary'}
];

const arr2 = [
  {id: 1, salary: 50000},
  {id: 2, salary: 60000},
  {id: 4, salary: 70000}
];

const common = arr1.filter(obj1 => arr2.find(obj2 => obj2.id === obj1.id));
console.log(common); // [{id: 1, name: 'John'}, {id: 2, name: 'Mark'}]

const onlyInArr1 = arr1.filter(obj1 => !arr2