使用Java代码捕获XSD验证规则违规。下面是一个示例，其中在解析XML时捕获规则违规并输出错误消息：

try {
  SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
  Schema schema = factory.newSchema(new File("yourSchema.xsd"));
  Validator validator = schema.newValidator();
  validator.setErrorHandler(new ErrorHandler() {
    public void warning(SAXParseException e) throws SAXException {
      System.out.println("Warning: " + e.getMessage());
    }
    public void error(SAXParseException e) throws SAXException {
      System.out.println("Error: " + e.getMessage());
    }
    public void fatalError(SAXParseException e) throws SAXException {
      System.out.println("Fatal Error: " + e.getMessage());
    }
  });
  validator.validate(new StreamSource(new File("yourXML.xml")));
} catch (SAXException e) {
  e.printStackTrace();
} catch (IOException e) {
  e.printStackTrace();
}