Android和AWSAPIGateway不工作
创始人
2024-10-08 05:01:14
0

检查以下几个方面:

  1. 检查是否使用了正确的API地址和密钥等认证信息。

  2. 确保您的Android设备已连接到可访问API的网络。

  3. 检查您的AWS API Gateway配置是否正确,并且确保您的API的部署状态为“已发布”。

以下是一个简单的示例,说明如何在Android中使用AWS API Gateway:

public class ApiGatewayClient {

    private static final String TAG = ApiGatewayClient.class.getSimpleName();

    private static final String API_REGION = "YOUR-API-REGION";
    private static final String API_ID = "YOUR-API-ID";
    private static final String API_STAGE = "YOUR-API-STAGE";
    private static final String API_KEY = "YOUR-API-KEY";

    private static final String API_ENDPOINT =
            String.format("https://%s.execute-api.%s.amazonaws.com/%s/",
                    API_ID, API_REGION, API_STAGE);

    private final OkHttpClient okHttpClient;
    private final Gson gson;

    public ApiGatewayClient() {
        this.okHttpClient = new OkHttpClient.Builder().build();
        this.gson = new Gson();
    }

    public void callApi(String path, Map queryParameters,
            ApiCallback callback) {

        HttpUrl.Builder urlBuilder = HttpUrl.parse(API_ENDPOINT + path).newBuilder();

        for (Map.Entry entry : queryParameters.entrySet()) {
            urlBuilder.addQueryParameter(entry.getKey(), entry.getValue());
        }

        String url = urlBuilder.build().toString();

        Request request = new Request.Builder()
                .header("x-api-key", API_KEY)
                .url(url)
                .build();

        okHttpClient.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {
                Log.e(TAG, "API call failed", e);
                callback.onError(e);
            }

            @Override
            public void onResponse(Call call, Response response) throws IOException {
                String responseBody = response.body().string();
                Log.d(TAG, "API response: " + responseBody);
                ApiResponse apiResponse = gson.fromJson(responseBody, ApiResponse.class);
                if (response.isSuccessful()) {
                    callback.onSuccess(apiResponse);
                } else {
                    callback

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