以下是一个示例代码,用于计算按行列排列的时间范围的重叠长度:
def calculate_overlap(intervals):
# 计算行和列的最大值和最小值
min_row = min(interval[0] for interval in intervals)
max_row = max(interval[1] for interval in intervals)
min_col = min(interval[2] for interval in intervals)
max_col = max(interval[3] for interval in intervals)
# 创建一个二维数组,用于记录每个时间点的重叠次数
overlap_matrix = [[0] * (max_col + 1) for _ in range(max_row + 1)]
# 在二维数组中标记重叠的时间范围
for interval in intervals:
for i in range(interval[0], interval[1] + 1):
for j in range(interval[2], interval[3] + 1):
overlap_matrix[i][j] += 1
# 计算重叠时间范围的长度
overlap_length = 0
for i in range(min_row, max_row + 1):
for j in range(min_col, max_col + 1):
if overlap_matrix[i][j] > 1:
overlap_length += 1
return overlap_length
# 示例用法
intervals = [[1, 3, 2, 4], [2, 4, 3, 6], [3, 5, 1, 5]]
overlap_length = calculate_overlap(intervals)
print(overlap_length)
在上述示例中,intervals
是一个包含多个时间范围的列表,每个时间范围由四个整数表示,分别是起始行、结束行、起始列和结束列。函数calculate_overlap
通过创建一个二维数组来记录每个时间点的重叠次数,然后计算重叠时间范围的长度。在示例用法中,输出结果为4,表示重叠时间范围的长度为4。
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