在Angular中,canActivate
方法的返回值类型应该是boolean
或者Observable
。如果canActivate
方法返回的是Observable
,但是无法正常工作,可能是因为Observable
没有正确的订阅或者处理错误。下面是一个包含代码示例的解决方法:
canActivate
方法返回的是Observable
类型。import { Injectable } from '@angular/core';
import { CanActivate, ActivatedRouteSnapshot, RouterStateSnapshot, Router } from '@angular/router';
import { Observable } from 'rxjs';
@Injectable()
export class AuthGuard implements CanActivate {
constructor(private router: Router) {}
canActivate(
next: ActivatedRouteSnapshot,
state: RouterStateSnapshot): Observable {
// 返回一个Observable类型的结果
return this.checkIfUserIsLoggedIn();
}
private checkIfUserIsLoggedIn(): Observable {
// 在这里检查用户是否已登录
// 返回一个Observable类型的结果
}
}
Observable
。import { Component, OnInit } from '@angular/core';
import { AuthService } from '../auth.service';
@Component({
selector: 'app-my-component',
template: `
User is logged in
User is not logged in
`
})
export class MyComponent implements OnInit {
userLoggedIn: boolean;
constructor(private authService: AuthService) { }
ngOnInit() {
// 订阅Observable
this.authService.checkIfUserIsLoggedIn().subscribe(
(loggedIn: boolean) => {
this.userLoggedIn = loggedIn;
},
(error) => {
// 处理错误
}
);
}
}
Observable
时处理错误。import { Injectable } from '@angular/core';
import { HttpClient } from '@angular/common/http';
import { Observable } from 'rxjs';
@Injectable()
export class AuthService {
constructor(private http: HttpClient) { }
checkIfUserIsLoggedIn(): Observable {
return this.http.get('/api/user/loggedin').pipe(
catchError((error) => {
// 处理错误
return of(false); // 返回默认值
})
);
}
}
通过以上方法,你可以确保Observable
在Angular守卫的canActivate
方法中正常工作,并正确地订阅和处理错误。