要解决Android Room嵌入关系忽略WHERE条件的问题,可以按照以下步骤进行:
示例代码:
@Entity(tableName = "user")
public class User {
@PrimaryKey
public int id;
public String name;
}
@Entity(tableName = "post", foreignKeys = @ForeignKey(entity = User.class, parentColumns = "id", childColumns = "userId", onDelete = ForeignKey.CASCADE))
public class Post {
@PrimaryKey
public int id;
public String title;
@ColumnInfo(name = "userId")
public int userId;
}
public class UserWithPosts {
@Embedded
public User user;
@Relation(parentColumn = "id", entityColumn = "userId", entity = Post.class)
public List posts;
}
示例代码:
@Dao
public interface UserDao {
@Transaction
@Query("SELECT * FROM user WHERE id = :userId")
LiveData getUserWithPosts(int userId);
}
示例代码:
@Dao
public interface UserDao {
@Transaction
@Query("SELECT * FROM user INNER JOIN post ON user.id = post.userId WHERE user.id = :userId")
LiveData getUserWithPosts(int userId);
}
通过按照上述步骤操作,您应该能够解决Android Room嵌入关系忽略WHERE条件的问题。确保在定义实体类和关系时正确设置FOREIGN KEY和关系注解,并在查询时使用适当的WHERE条件。如果问题仍然存在,可以尝试使用INNER JOIN来手动执行嵌入查询并使用WHERE条件筛选结果。