要解决Android WorkManager不触发两个计划工作之一的问题，你可以使用以下代码示例：

1. 创建一个WorkManager初始化类，用于设置和启动WorkManager：

public class WorkManagerInitializer extends Application {
    @Override
    public void onCreate() {
        super.onCreate();
        startWorkManager();
    }

    private void startWorkManager() {
        Constraints constraints = new Constraints.Builder()
                .setRequiredNetworkType(NetworkType.CONNECTED)
                .build();

        OneTimeWorkRequest workRequest1 = new OneTimeWorkRequest.Builder(YourWorker1.class)
                .setConstraints(constraints)
                .build();

        OneTimeWorkRequest workRequest2 = new OneTimeWorkRequest.Builder(YourWorker2.class)
                .setConstraints(constraints)
                .build();

        WorkManager.getInstance(this).beginWith(workRequest1, workRequest2).enqueue();
    }
}

2. 创建两个工作类YourWorker1和YourWorker2，用于执行具体的工作任务：

public class YourWorker1 extends Worker {
    public YourWorker1(@NonNull Context context, @NonNull WorkerParameters workerParams) {
        super(context, workerParams);
    }

    @NonNull
    @Override
    public Result doWork() {
        // 执行第一个工作任务的逻辑
        return Result.success();
    }
}

public class YourWorker2 extends Worker {
    public YourWorker2(@NonNull Context context, @NonNull WorkerParameters workerParams) {
        super(context, workerParams);
    }

    @NonNull
    @Override
    public Result doWork() {
        // 执行第二个工作任务的逻辑
        return Result.success();
    }
}

3. 确保在AndroidManifest.xml文件中注册工作类和WorkManager初始化类：

    ...

通过这种方式，你可以在应用启动时初始化并启动WorkManager，并确保两个工作任务都会触发执行。