以下是一个示例代码，演示如何按照每个id连续天数的计数进行分组：

# 输入数据
data = [
    {'id': 1, 'date': '2022-01-01'},
    {'id': 1, 'date': '2022-01-02'},
    {'id': 1, 'date': '2022-01-03'},
    {'id': 2, 'date': '2022-01-01'},
    {'id': 2, 'date': '2022-01-02'},
    {'id': 3, 'date': '2022-01-01'},
    {'id': 3, 'date': '2022-01-03'},
]

# 按照id进行分组
groups = {}
for item in data:
    id = item['id']
    if id not in groups:
        groups[id] = []
    groups[id].append(item)

# 计算每个id的连续天数的计数
count_groups = {}
for id, group in groups.items():
    count = 1
    count_group = []
    for i in range(1, len(group)):
        prev_date = group[i-1]['date']
        curr_date = group[i]['date']
        prev_day = int(prev_date[-2:])
        curr_day = int(curr_date[-2:])
        if curr_day - prev_day == 1:
            count += 1
        else:
            count_group.append(count)
            count = 1
    count_group.append(count)
    count_groups[id] = count_group

# 输出结果
for id, counts in count_groups.items():
    print(f"ID {id}: {counts}")

运行上述代码的结果将输出每个id的连续天数的计数。例如，对于给定的数据，输出将如下所示：

ID 1: [3]
ID 2: [2]
ID 3: [1, 1]

这表示id为1的数据连续出现了3天，id为2的数据连续出现了2天，id为3的数据分别连续出现了1天和1天。